Termination w.r.t. Q of the following Term Rewriting System could not be shown:
Q restricted rewrite system:
The TRS R consists of the following rules:
a2(f, a2(f, a2(g, a2(g, x)))) -> a2(g, a2(g, a2(g, a2(f, a2(f, a2(f, x))))))
Q is empty.
↳ QTRS
↳ Non-Overlap Check
Q restricted rewrite system:
The TRS R consists of the following rules:
a2(f, a2(f, a2(g, a2(g, x)))) -> a2(g, a2(g, a2(g, a2(f, a2(f, a2(f, x))))))
Q is empty.
The TRS is non-overlapping. Hence, we can switch to innermost.
↳ QTRS
↳ Non-Overlap Check
↳ QTRS
↳ DependencyPairsProof
Q restricted rewrite system:
The TRS R consists of the following rules:
a2(f, a2(f, a2(g, a2(g, x)))) -> a2(g, a2(g, a2(g, a2(f, a2(f, a2(f, x))))))
The set Q consists of the following terms:
a2(f, a2(f, a2(g, a2(g, x0))))
Q DP problem:
The TRS P consists of the following rules:
A2(f, a2(f, a2(g, a2(g, x)))) -> A2(g, a2(g, a2(f, a2(f, a2(f, x)))))
A2(f, a2(f, a2(g, a2(g, x)))) -> A2(f, a2(f, x))
A2(f, a2(f, a2(g, a2(g, x)))) -> A2(g, a2(f, a2(f, a2(f, x))))
A2(f, a2(f, a2(g, a2(g, x)))) -> A2(f, a2(f, a2(f, x)))
A2(f, a2(f, a2(g, a2(g, x)))) -> A2(f, x)
A2(f, a2(f, a2(g, a2(g, x)))) -> A2(g, a2(g, a2(g, a2(f, a2(f, a2(f, x))))))
The TRS R consists of the following rules:
a2(f, a2(f, a2(g, a2(g, x)))) -> a2(g, a2(g, a2(g, a2(f, a2(f, a2(f, x))))))
The set Q consists of the following terms:
a2(f, a2(f, a2(g, a2(g, x0))))
We have to consider all minimal (P,Q,R)-chains.
↳ QTRS
↳ Non-Overlap Check
↳ QTRS
↳ DependencyPairsProof
↳ QDP
↳ DependencyGraphProof
Q DP problem:
The TRS P consists of the following rules:
A2(f, a2(f, a2(g, a2(g, x)))) -> A2(g, a2(g, a2(f, a2(f, a2(f, x)))))
A2(f, a2(f, a2(g, a2(g, x)))) -> A2(f, a2(f, x))
A2(f, a2(f, a2(g, a2(g, x)))) -> A2(g, a2(f, a2(f, a2(f, x))))
A2(f, a2(f, a2(g, a2(g, x)))) -> A2(f, a2(f, a2(f, x)))
A2(f, a2(f, a2(g, a2(g, x)))) -> A2(f, x)
A2(f, a2(f, a2(g, a2(g, x)))) -> A2(g, a2(g, a2(g, a2(f, a2(f, a2(f, x))))))
The TRS R consists of the following rules:
a2(f, a2(f, a2(g, a2(g, x)))) -> a2(g, a2(g, a2(g, a2(f, a2(f, a2(f, x))))))
The set Q consists of the following terms:
a2(f, a2(f, a2(g, a2(g, x0))))
We have to consider all minimal (P,Q,R)-chains.
The approximation of the Dependency Graph contains 1 SCC with 3 less nodes.
↳ QTRS
↳ Non-Overlap Check
↳ QTRS
↳ DependencyPairsProof
↳ QDP
↳ DependencyGraphProof
↳ QDP
Q DP problem:
The TRS P consists of the following rules:
A2(f, a2(f, a2(g, a2(g, x)))) -> A2(f, a2(f, x))
A2(f, a2(f, a2(g, a2(g, x)))) -> A2(f, a2(f, a2(f, x)))
A2(f, a2(f, a2(g, a2(g, x)))) -> A2(f, x)
The TRS R consists of the following rules:
a2(f, a2(f, a2(g, a2(g, x)))) -> a2(g, a2(g, a2(g, a2(f, a2(f, a2(f, x))))))
The set Q consists of the following terms:
a2(f, a2(f, a2(g, a2(g, x0))))
We have to consider all minimal (P,Q,R)-chains.